In this post, we are going to discuss "How to calculate concrete volume and it's ingredients?"
How to Calculate Concrete Volume?
If it is a volume, then we know there must be 3 dimensions, Length, Height, Width or Breadth.
For Slab, If we need to calculate the concrete volume,
Volume = Length x Breadth x Width / Thickness = 5 x 3 x 0.125 = 3.75 cu.m
For Beam, If we need to calculate the concrete volume,
Volume = Length x Breadth x Width = 5 x 0.6 x 0.3 = 0.9 cu.m
For Column, If we need to calculate the concrete volume,
Rectangular Column, Volume = Height x Breadth x Width = 5 x 0.6 x 0.3 = 0.9 cu.m
Circular Column , Volume = 𝛑r˄2h = 3.14 x (0.15)˄2 x 5 = 0.35 cu.m
CONCRETE INGREDIENTS CALCULATION:
For cement, sand and coarse aggregate.
This is a volumetric calculation.
Assuming we need 2 cu.m of concrete for M20 mix,(Mix ratio, M20 = 1:1.5:3)
Total part of the concrete = 1 + 1.5 + 3 = 5.5 parts
Therefore, Cement Quantity = (Cement Part / Concrete Parts) x Concrete Volume
= (1 / 5.5) x Concrete Volume = (1 / 5.5) x 2 = 0.3636 cu.m
Density of Cement = 1440 kg / cu.m = 0.3636 x 1440 = 523 kg = 10.5 approx.bags
Sand Quantity = (Sand Part / Concrete Parts) x Concrete Volume = (1 / 5.5) x 2 = 0.5454 cu.m
Coarse Aggregate = (Coarse aggregate part / Concrete parts) x Concrete Volume = (3 / 5.5) x 2 = 1.09 cu.m
WATER CEMENT RATIO:
According to IS 10262 (2009), Assuming Water-Cement Ratio for the concrete as 0.45
Required amount of water = W/C ratio x Cement volume
Therefore, Water = 0.45 x 0.3636 = 0.16362 cu.m
[Unit Weight of Water = 1000 liters/cu.m]
Required amount of water = 0.16362 x 1000 = 163.32 liters
Therefore,we need 10.5 bags of cement , 0.5454 cu.m of sand , 1.09 cu.m of coarse aggregates and 163.62 liters of water.
How to Calculate Concrete Volume?
If it is a volume, then we know there must be 3 dimensions, Length, Height, Width or Breadth.
For Slab, If we need to calculate the concrete volume,
Volume = Length x Breadth x Width / Thickness = 5 x 3 x 0.125 = 3.75 cu.m
For Beam, If we need to calculate the concrete volume,
For Column, If we need to calculate the concrete volume,
Circular Column , Volume = 𝛑r˄2h = 3.14 x (0.15)˄2 x 5 = 0.35 cu.m
CONCRETE INGREDIENTS CALCULATION:
For cement, sand and coarse aggregate.
This is a volumetric calculation.
Assuming we need 2 cu.m of concrete for M20 mix,(Mix ratio, M20 = 1:1.5:3)
Total part of the concrete = 1 + 1.5 + 3 = 5.5 parts
Therefore, Cement Quantity = (Cement Part / Concrete Parts) x Concrete Volume
= (1 / 5.5) x Concrete Volume = (1 / 5.5) x 2 = 0.3636 cu.m
Density of Cement = 1440 kg / cu.m = 0.3636 x 1440 = 523 kg = 10.5 approx.bags
Sand Quantity = (Sand Part / Concrete Parts) x Concrete Volume = (1 / 5.5) x 2 = 0.5454 cu.m
Coarse Aggregate = (Coarse aggregate part / Concrete parts) x Concrete Volume = (3 / 5.5) x 2 = 1.09 cu.m
WATER CEMENT RATIO:
According to IS 10262 (2009), Assuming Water-Cement Ratio for the concrete as 0.45
Required amount of water = W/C ratio x Cement volume
Therefore, Water = 0.45 x 0.3636 = 0.16362 cu.m
[Unit Weight of Water = 1000 liters/cu.m]
Required amount of water = 0.16362 x 1000 = 163.32 liters
Therefore,we need 10.5 bags of cement , 0.5454 cu.m of sand , 1.09 cu.m of coarse aggregates and 163.62 liters of water.
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